Edit this pageOld revisionsBacklinksBack to top <latex> \frac{3}{4 \pi} \sqrt{4 \cdot x^2 12}\\ \lim_{n \to \infty} \sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6} e^{i \pi} + 1 = 0 \\ </latex> ∫x2dx=13x3∴∫10x2dx=13 luminous/latex_test.txt Last modified: 2024-11-08 15:23by nik