<latex>

  \frac{3}{4 \pi}   \sqrt{4 \cdot x^2   12}\\
  \lim_{n \to \infty}
  \sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6}
  e^{i \pi} + 1 = 0 \\

</latex>

x2dx=13x3

  • luminous/latex_test.txt
  • Last modified: 2024-11-08 15:23
  • by nik